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In an ap the sum of first ten terms is - 150

WebIn an AP, the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the AP. Medium Solution Verified by Toppr S 10=−150 S n= 2n[2a+(n−1)d] S 10= … WebThe third term of an AP is four times the sixth term and the sum of the first ten terms is 150. Find a) The first term and the common difference b) The least number of terms of the Arithmetic Progression which must be taken for the sum to be negative Question Transcribed Image Text: 3.

In an AP, the sum of the first ten terms is 80 and the sum of

WebSum In an A.P., the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the A.P. Advertisement Remove all ads Solution Here, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a10. WebMar 23, 2024 · In an A.P. the sum of the first ten terms is -150 and the sum of its next ten terms is -550. Find first term of A.P. Verified 182.4k + views Hint: In the above equation we will use the formula of the sum of the first n terms of an A.P. which is as follows: S n = n 2 [ … earth shoes sale clearance https://frenchtouchupholstery.com

In an A.P., the sum of first ten terms is −150 and the sum …

WebExpert Answer Transcribed image text: 3. The third term of an AP is four times the sixth term and the sum of the first ten terms is 150. Find a) The first term and the common difference b) The least number of terms of the Arithmetic Progression which must be taken for the sum to be negative [5] 4. WebThe sum of the first five terms an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. WebQ. The sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first … earth shoes out of business

The sum of first 10 terms of an AP is 150 and the sum of …

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In an ap the sum of first ten terms is - 150

In an AP, the sum of first ten terms is -150 and the sum of its next ...

WebQ. The sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. WebApr 2, 2024 · The median of the distribution given below is 14.4. Find the values of x and y, if the sum of frequency is 20. Find the common difference ' d ' of an AP whose first term is 10 and the sum of the first 14 terms is 1505 . For what value of ' n ', are the nth terms of the APs : 9,7,5,….. and 15,12,9,…. the same?

In an ap the sum of first ten terms is - 150

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WebHere, we are given S 10 = - 150 and sum of the next ten terms is - 550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a 10. First term = a. Last term = a 10. As, a n = a + ( n - 1) d. For the 10 th term, a 10 = a + ( 10 - 1) d. = a + 9 d. So, here we can find the sum of the n terms of the ... WebApr 8, 2024 · Given sum of first ten terms = − 150. We know that Sum of n terms of AP S n = n 2 [ 2 a + ( n − 1) d] Therefore, ⇒ S 10 = 10 2 [ 2 a + ( 10 − 1) d] ⇒ − 150 = 5 [ 2 a + 9 d] ⇒ …

WebThe sum of n terms of an AP can be easily found out using a simple formula which says that, if we have an AP whose first term is a and the common difference is d, then the formula of the sum of n terms of the AP is S n = … WebJun 24, 2024 · In an A.P., the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the A.P. Advertisement Expert-Verified Answer 44 people found it helpful nikitasingh79 Answer: The AP is 3, - 1,- 5 ,- 9,…... Step-by-step explanation: Given : S10 = - 150 and sum of its next 10 terms is - 550.

WebOct 20, 2024 · In an AP the sum of first ten terms is -150 and the sum of its next 10 terms is -550. Find the AP. Is this the question you’re looking for? Advertisement Expert-Verified Answer 49 people found it helpful Hey there !! Let a be the first term and d be the common difference of the given AP . S₁₀ = -150. ⇒ Sn = n/2 [ 2a + (n-1)d] WebMay 14, 2024 · Given: Sum of first ten terms that is, S 10 = -150 and Sum of next ten terms is -550. To find: The A.P. Solution: Let, first term = a Last term = a n We know in an A.P, a n = a + (n – 1) d. For n = 10. a n = a + (10 - 1)d. a n = a + 9d. We know, sum of n terms. s n = \(\frac{n}{2}[a + l]\). l and a n means the last term.. Put the value of l in (1),So, S 10 = …

WebClick here👆to get an answer to your question ️ In an A.P. the sum of first ten terms is \( - 150 \) and the sum of its next ten terms is - Find the A.P CBSE 2010 Sum of the first 14 terms of an A.P. is 1505 and its first term is \( 10 . \) Find its \( 25 ^ { \text { th } } \) term

WebMar 19, 2024 · Given that sum of the first 10 terms of an A.P. is -150. S10 = -150. And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum … earth shoes return need labelWebJul 29, 2024 · In an AP, the sum of first ten terms is -150 and the sum of its next ten terms is -550. Find the A.P.I have provided the easiest solution of above question, ... AboutPressCopyrightContact... earth shoes powerpath footbedWebMar 27, 2024 · C. I Frequency 10 vicle, me ACB be 0-15 15-30 30-45 45-60 ore than type ogive' for the given data. 18 40 20 60-75 12 29) The sum of the reciprocals of Rehman's ages 3years ago and 5 years from now is Find his present age. ct paid leave flyerWebS n = n/2 {2a + (n − 1)d} Given that sum of the first 10 terms of an A.P. is -150. S 10 = -150 And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 … ct paid leave filingct paid leave log inWebJul 29, 2024 · In an AP, the sum of first ten terms is -150 and the sum of its next ten terms is -550. Find the A.P.I have provided the easiest solution of above question, ... AboutPressCopyrightContact... ct paid leave on w2WebIn this A.P., sum of first 10 terms is Easy Solution Verified by Toppr 15,10,5,...…. a=15 d=10−15=−5 S n= 2n[2a+(n−1)d] S 10= 210[2×15+(10−1)(−5)] =5[30−5×9] =5[30−45] =5(−15)=−75. Was this answer helpful? 0 0 Similar questions For an arithmetic progression: 5, 211,6, 213,… then T 40−T 20=? Medium View solution > ct paid leave fmla